H=-16t^2+vt+h. Find initial height and velocity if the maximum height is 412 feet 5 seconds after launch?

If an object is launched straight up into the air from a starting height of h. feet, then the height of the object after t seconds is approximately h=-16t^2+vt+h. feet, where v is the initial velocity of the object. Find the starting height and initial velocity of an object that attains a maximum height of 412 feet 5 seconds after being launched